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kbtree: pointer UB and unitialized value fixes

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- don't underflow itr->p pointer (C standard only allows one past the end, not
  one before the beginning)
- make sure itr->p->i is always initialized (even when not used)
- don't rely on `NULL < &object` (likely UB)
This commit is contained in:
Björn Linse 2019-05-18 13:37:57 +02:00
parent 5625c7d8e1
commit b247c6fd22
1 changed files with 12 additions and 5 deletions
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17
src/nvim/lib/kbtree.h
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@ -317,7 +317,7 @@
#define __KB_ITR(name, key_t, kbnode_t) \
static inline void kb_itr_first_##name(kbtree_##name##_t *b, kbitr_##name##_t *itr) \
{ \
itr->p = 0; \
itr->p = NULL; \
if (b->n_keys == 0) return; \
itr->p = itr->stack; \
itr->p->x = b->root; itr->p->i = 0; \
@ -329,7 +329,7 @@
} \
static inline int kb_itr_next_##name(kbtree_##name##_t *b, kbitr_##name##_t *itr) \
{ \
if (itr->p < itr->stack) return 0; \
if (itr->p == NULL) return 0; \
for (;;) { \
++itr->p->i; \
while (itr->p->x && itr->p->i <= itr->p->x->n) { \
@ -337,22 +337,28 @@
itr->p[1].x = itr->p->x->is_internal? __KB_PTR(b, itr->p->x)[itr->p->i] : 0; \
++itr->p; \
} \
if (itr->p == itr->stack) { \
itr->p = NULL; \
return 0; \
} \
--itr->p; \
if (itr->p < itr->stack) return 0; \
if (itr->p->x && itr->p->i < itr->p->x->n) return 1; \
} \
} \
static inline int kb_itr_prev_##name(kbtree_##name##_t *b, kbitr_##name##_t *itr) \
{ \
if (itr->p < itr->stack) return 0; \
if (itr->p == NULL) return 0; \
for (;;) { \
while (itr->p->x && itr->p->i >= 0) { \
itr->p[1].x = itr->p->x->is_internal? __KB_PTR(b, itr->p->x)[itr->p->i] : 0; \
itr->p[1].i = itr->p[1].x ? itr->p[1].x->n : -1; \
++itr->p; \
} \
if (itr->p == itr->stack) { \
itr->p = NULL; \
return 0; \
} \
--itr->p; \
if (itr->p < itr->stack) return 0; \
--itr->p->i; \
if (itr->p->x && itr->p->i >= 0) return 1; \
} \
@ -374,6 +380,7 @@
itr->p[1].x = itr->p->x->is_internal? __KB_PTR(b, itr->p->x)[i + 1] : 0; \
++itr->p; \
} \
itr->p->i = 0; \
return 0; \
} \
static inline int kb_itr_get_##name(kbtree_##name##_t *b, key_t k, kbitr_##name##_t *itr) \