signal: Add a proper comment about preempt_disable() in ptrace_stop()
Commit 53da1d9456
("fix ptrace slowness") added a preempt-disable section
between read_unlock() and the following schedule() invocation without
explaining why it is needed.
Replace the existing contentless comment with a proper explanation to
clarify that it is not needed for correctness but for performance reasons.
Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Acked-by: Oleg Nesterov <oleg@redhat.com>
Link: https://lore.kernel.org/r/20230803100932.325870-2-bigeasy@linutronix.de
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@ -2329,10 +2329,22 @@ static int ptrace_stop(int exit_code, int why, unsigned long message,
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do_notify_parent_cldstop(current, false, why);
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/*
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* Don't want to allow preemption here, because
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* sys_ptrace() needs this task to be inactive.
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* The previous do_notify_parent_cldstop() invocation woke ptracer.
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* One a PREEMPTION kernel this can result in preemption requirement
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* which will be fulfilled after read_unlock() and the ptracer will be
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* put on the CPU.
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* The ptracer is in wait_task_inactive(, __TASK_TRACED) waiting for
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* this task wait in schedule(). If this task gets preempted then it
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* remains enqueued on the runqueue. The ptracer will observe this and
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* then sleep for a delay of one HZ tick. In the meantime this task
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* gets scheduled, enters schedule() and will wait for the ptracer.
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*
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* XXX: implement read_unlock_no_resched().
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* This preemption point is not bad from a correctness point of
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* view but extends the runtime by one HZ tick time due to the
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* ptracer's sleep. The preempt-disable section ensures that there
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* will be no preemption between unlock and schedule() and so
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* improving the performance since the ptracer will observe that
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* the tracee is scheduled out once it gets on the CPU.
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*/
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preempt_disable();
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read_unlock(&tasklist_lock);
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