cgroup/cpuset: remove fetch_xcpus
Both fetch_xcpus and user_xcpus functions are used to retrieve the value of exclusive_cpus. If exclusive_cpus is not set, cpus_allowed is the implicit value used as exclusive in a local partition. I can not imagine a scenario where effective_xcpus is not empty when exclusive_cpus is empty. Therefore, I suggest removing the fetch_xcpus function. Signed-off-by: Chen Ridong <chenridong@huawei.com> Reviewed-by: Waiman Long <longman@redhat.com> Signed-off-by: Tejun Heo <tj@kernel.org>
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@ -771,13 +771,6 @@ static inline bool xcpus_empty(struct cpuset *cs)
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cpumask_empty(cs->exclusive_cpus);
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}
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static inline struct cpumask *fetch_xcpus(struct cpuset *cs)
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{
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return !cpumask_empty(cs->exclusive_cpus) ? cs->exclusive_cpus :
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cpumask_empty(cs->effective_xcpus) ? cs->cpus_allowed
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: cs->effective_xcpus;
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}
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/*
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* cpusets_are_exclusive() - check if two cpusets are exclusive
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*
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@ -785,8 +778,8 @@ static inline struct cpumask *fetch_xcpus(struct cpuset *cs)
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*/
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static inline bool cpusets_are_exclusive(struct cpuset *cs1, struct cpuset *cs2)
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{
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struct cpumask *xcpus1 = fetch_xcpus(cs1);
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struct cpumask *xcpus2 = fetch_xcpus(cs2);
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struct cpumask *xcpus1 = user_xcpus(cs1);
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struct cpumask *xcpus2 = user_xcpus(cs2);
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if (cpumask_intersects(xcpus1, xcpus2))
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return false;
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@ -2585,7 +2578,7 @@ static int update_cpumask(struct cpuset *cs, struct cpuset *trialcs,
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invalidate = true;
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rcu_read_lock();
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cpuset_for_each_child(cp, css, parent) {
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struct cpumask *xcpus = fetch_xcpus(trialcs);
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struct cpumask *xcpus = user_xcpus(trialcs);
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if (is_partition_valid(cp) &&
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cpumask_intersects(xcpus, cp->effective_xcpus)) {
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