signal: Replace BUG_ON()s
These really can be handled gracefully without killing the machine. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Frederic Weisbecker <frederic@kernel.org> Reviewed-by: Oleg Nesterov <oleg@redhat.com> Acked-by: Peter Zijlstra (Intel) <peterz@infradead.org>
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@ -1938,10 +1938,11 @@ struct sigqueue *sigqueue_alloc(void)
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void sigqueue_free(struct sigqueue *q)
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{
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unsigned long flags;
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spinlock_t *lock = ¤t->sighand->siglock;
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unsigned long flags;
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BUG_ON(!(q->flags & SIGQUEUE_PREALLOC));
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if (WARN_ON_ONCE(!(q->flags & SIGQUEUE_PREALLOC)))
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return;
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/*
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* We must hold ->siglock while testing q->list
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* to serialize with collect_signal() or with
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@ -1969,7 +1970,10 @@ int send_sigqueue(struct sigqueue *q, struct pid *pid, enum pid_type type)
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unsigned long flags;
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int ret, result;
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BUG_ON(!(q->flags & SIGQUEUE_PREALLOC));
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if (WARN_ON_ONCE(!(q->flags & SIGQUEUE_PREALLOC)))
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return 0;
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if (WARN_ON_ONCE(q->info.si_code != SI_TIMER))
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return 0;
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ret = -1;
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rcu_read_lock();
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@ -2004,7 +2008,6 @@ int send_sigqueue(struct sigqueue *q, struct pid *pid, enum pid_type type)
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* If an SI_TIMER entry is already queue just increment
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* the overrun count.
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*/
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BUG_ON(q->info.si_code != SI_TIMER);
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q->info.si_overrun++;
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result = TRACE_SIGNAL_ALREADY_PENDING;
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goto out;
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