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euclidean-perfection/euclideanp.py

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# Copyright (C) 2014 kcotugno
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# Distributed under the MIT software license, see the accompanying
# LICENSE file or http://www.opensource.org/licenses/MIT
#
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# Author: kcotugno
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# Date 5/30/14
import math
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# This function check if a number is prime first by testing for the #2, then if
# it less than 2 or divisible by 2. If non of these pre-checks return, it runs
# through a loop which goes from 3 to the sqrt of the number only testing it
# against odd numbers.
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def isprime(num):
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if num == 2:
return True
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if num < 2 or num % 2 == 0:
return False
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for i in range(3, int(math.sqrt(num)) + 1, 2):
if num % i == 0:
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return False
return True
# The algorithm calculates the numbers by continually finding numbers in double
# proportion from 1 until the sum of them is a prime number. Then, it takes the
# product of the prime and last number in the proportion. Whence perfect numbers
# are found.
def perfection(calc):
proportionals = [1]
perfect = []
p = 0
while p < calc:
psum = 0
while isprime(psum) == False:
proportionals.append((proportionals[len(proportionals) - 1]) \
* 2)
psum = 0
for i in proportionals:
psum = psum + i
#print(psum)
p += 1
perfect.append(psum * proportionals[len(proportionals) - 1])
return perfect
def main():
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print("Euclidean Perfection")
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print("Copyright (C) 2014 kcotugno")
print("Distributed under the MIT software license, see the accompanying")
print("LICENSE file or http://www.opensource.org/licenses/MIT\n")
gotinput = False
while gotinput == False:
i = input("Please enter the desired number of perfection "
"to calculate: ")
try:
int(i)
except:
print("Please only enter positive integers..."
"and not too large :)\n")
else:
i = int(i)
if i <= 0:
print("Please only enter positive integers..."
"and not too large :)\n")
else:
gotinput = True
perfect = perfection(i)
index = 0
for p in perfect:
index += 1
print(format("{0}. {1}".format(index, p)))
if __name__ == "__main__":
main()